QJEEM21Ph15e2: JEE Main 2021 Physics - Class 12 JEEM21Ph15e2 Solution: Two equal capacitors are first connected in series and then in…

Given, C₁ = C₂ = C

When both capacitors are connected in series, their equivalent capacitance will be

${1 \over {{C_s}}} = {1 \over C} + {1 \over C} = {2 \over C}$

$\Rightarrow {C_s} = {C \over 2}$

When both capacitors are connected in parallel, their equivalent capacitance will be

C_p = C + C = 2C

$\therefore$ The ratio of equivalent capacitance in series and parallel combination is

${{{C_s}} \over {{C_p}}} = {{C/2} \over {2C}} = {1 \over 4}$

$\therefore$ C_s : C_p = 1 : 4