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QJEEM21Ph14aa: JEE Main 2021 Physics - Class 11 JEEM21Ph14aa Solution: An object of mass 'm' is being moved with a constant velocity…
An object of mass 'm' is being moved with a constant velocity under the action of an applied force of 2N along a frictionless surface with following surface profile.

The correct applied force vs distance graph will be :

The correct applied force vs distance graph will be :
Multiple Choice Options
- A https://ik.imagekit.io/novatra/photos/ac94cd33ba8e810510a3f753eaeb4279eb5d900b37939b1fe59672a44ebee254.webp
- B https://ik.imagekit.io/novatra/photos/7cb3beb05eca6741242d166545a16af04e4336698e0d45d040b76796bdab3d6d.webp
- C https://ik.imagekit.io/novatra/photos/41cf49aca60dccdb5ed40868251aeadb20a6568ea581e519650cc5f3001eb366.webp
- D https://ik.imagekit.io/novatra/photos/5c51aaa16ec268363308eb0e92b86f581dcbe6bcc5370fe5e706faf4da396006.webp
Step-by-Step Verified Solution
During upward motion
F = 2N = (+ve) constant

During downward motion
F = 2N = ( ve) constant

Best possible answer is option (c)
F = 2N = (+ve) constant

During downward motion
F = 2N = ( ve) constant

Best possible answer is option (c)