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QJEEM21Ph10a0: JEE Main 2021 Physics - Class 11 JEEM21Ph10a0 Solution: Time period of a simple pendulum is T. The time taken to…

Time period of a simple pendulum is T. The time taken to complete 58{5 \over 8} oscillations starting from mean position is αβT{\alpha \over \beta }T . The value of α\alpha is _________.

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JEE Main 2021 (Online) 26th February Evening Shift Physics - Simple Harmonic Motion Question 88 English Explanation
58{5 \over 8} oscillation = 12{1 \over 2} oscillation + 18{1 \over 8} oscillation

From figure, A to B = 12{1 \over 2} oscillation and B to C is 18{1 \over 8} oscillation.

∴\therefore π+ θ=ωt\pi { + \,\theta = \omega t}

⇒\Rightarrow π+π6=ωt\pi { + {{\pi{} } \over 6}} = \omega t

⇒\Rightarrow 7π6=(2πT)t{{7\pi {} } \over 6} = \left( {{{2\pi {} } \over T}} \right)t

⇒\Rightarrow t = 7T12{{7T} \over {12}}

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