Verified Solution • 2025–26 Session moderate

QJEEM21Ph03b4: JEE Main 2021 Physics - Class 12 JEEM21Ph03b4 Solution: The logic circuit shown above is equivalent to :

JEE Main 2021 (Online) 24th February Evening Shift Physics - Semiconductor Question 127 English
The logic circuit shown above is equivalent to :

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/ffef7af316a74991ccbc5ac9365ba37df3760eec7e5240b1e72d4cb322dd9d06.webp
  • B https://ik.imagekit.io/novatra/photos/0b18bfdad19700560aad182ad82deb700b77083a4becfaa8a5316e144b7bbf33.webp
  • C https://ik.imagekit.io/novatra/photos/07a2f204c7ece2f6a5ff39a35532c86e834f93410e8f5b96a58f647a0a45bb62.webp
  • D https://ik.imagekit.io/novatra/photos/e3bc4a15855c87a837550d04301dfa1dc59aeae70f716ea1d41a425d9590c3bd.webp

Step-by-Step Verified Solution

The logic circuit is given as JEE Main 2021 (Online) 24th February Evening Shift Physics - Semiconductor Question 127 English Explanation 1
By using De-morgan’s theorem,

C=A+B‾‾=A‾.B‾‾=A‾.BC = \overline {A + \overline B } = \overline A .\overline{\overline B} = \overline A .B

This relation can be shown by the circuit drawn below

JEE Main 2021 (Online) 24th February Evening Shift Physics - Semiconductor Question 127 English Explanation 2

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