QJEEM21Maf8db: JEE Main 2021 Mathematics - Class 12 JEEM21Maf8db Solution: The area of the region S = { ( x , y ) : 3 x 2 ≤ 4 y ≤ 6 x + 24 …

Step-by-Step Verified Solution

For A & B

3x² = 6x + 24 $$\Rightarrow$$ x² $$-$$ 2x $$-$$ 8 = 0

$$\Rightarrow$$ x = $$-$$2, 4

Area $$=\underset{-2}{\overset{4}{\int }}\left(\frac{3}{2}x+6-\frac{3}{4}{x}^2\right)dx$$

$$={\left[\frac{3x^2}{4}+6x-\frac{x^3}{4}\right]}_{-2}^4=27$$