Verified Solution • 2025–26 Session moderate

QJEEM21Maf541: JEE Main 2021 Mathematics - Class 11 JEEM21Maf541 Solution: Team 'A' consists of 7 boys and n girls and Team 'B' has 4 boys …

Team 'A' consists of 7 boys and n girls and Team 'B' has 4 boys and 6 girls. If a total of 52 single matches can be arranged between these two teams when a boy plays against a boy and a girl plays against a girl, then n is equal to :

Multiple Choice Options

  • A 5
  • B 2
  • C 4
  • D 6

Step-by-Step Verified Solution

Total matches between boys of both team = 7C1×4C1=28{}^7{C_1} \times {}^4{C_1} = 28

Total matches between girls of both team = nC1 6C1=6n{}^n{C_1}\,{}^6{C_1} = 6n

Now, 28 + 6n = 52

⇒\Rightarrow n = 4

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