QJEEM21Maeb19: JEE Main 2021 Mathematics - Class 11 JEEM21Maeb19 Solution: If (2021) 3762 is divided by 17, then the remainder is…

2021 = 17m - 2

(2021)³⁷⁶² = (17m $-$ 2)³⁷⁶² = multiple of 17 + 2³⁷⁶²

= 17 $\lambda$ + 2² (2⁴)⁹⁴⁰

= 17 $\lambda$ + 4 (17 $-$ 1)⁹⁴⁰

= 17 $\lambda$ + 4 (17 $\mu$ + 1)

= 17k + 4; (k $\in$ I)

$\therefore$ Remainder = 4