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QJEEM21Mae94d: JEE Main 2021 Mathematics - Class 12 JEEM21Mae94d Solution: The values of λ and μ such that the system of equations x + y + …

The values of λ and μ such that the system of equations x+y+z=6, 3x+5y+5z=26, x+2y+λz=μ has no solution, are :

Multiple Choice Options

  • A λ = 3, μ = 5
  • B λ = 3, μ ≠ 10
  • C λ ≠ 2, μ = 10
  • D λ = 2, μ ≠ 10

Step-by-Step Verified Solution

x+y+z=6 ..... (i)

3x+5y+5z=26 .... (ii)

x+2y+λz=μ ..... (iii)

5×(i)−(ii)⇒2x=4⇒x=2

∴ from (i) and (iii)

y+z=4 ..... (iv)

2y+λz=μ−2 .....(v)

(v)−2×(iv)

⇒(λ−2)z=μ−10

⇒z=μ−10λ−2 & y=4−μ−10λ−2

∴ For no solution λ = 2 and μ ≠ 10.

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