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QJEEM21Maddd2: JEE Main 2021 Mathematics - Class 12 JEEM21Maddd2 Solution: Let f : R R be defined as f ( x ) = { − 4 3 x 3 + 2 x 2 + 3 x , …

Let f : R →\to R be defined as

f(x)={−43x3+2x2+3x,x>03xex,x≤0. Then f is increasing function in the interval

Multiple Choice Options

  • A (−12,2)\left( { - {1 \over 2},2} \right)
  • B (0,2)
  • C (−1,32)\left( { - 1,{3 \over 2}} \right)
  • D ( −- 3, −- 1)

Step-by-Step Verified Solution

f′(x){−4x2+4x+3x>03ex(1+x)x≤0

JEE Main 2021 (Online) 22th July Evening Shift Mathematics - Application of Derivatives Question 95 English Explanation
For x > 0, f′(x)=−4x2+4x+3f'(x) = - 4{x^2} + 4x + 3

f(x) is increasing in (−12,32)\left( { - {1 \over 2},{3 \over 2}} \right)

For x ≤\le 0, f'(x) = 3ex(1 + x)

f'(x) > 0 ∀\forall x ∈\in ( −- 1, 0)

⇒\Rightarrow f(x) is increasing in ( −- 1, 0)

So, in complete domain, f(x) is increasing in (−1,32)\left( { - 1,{3 \over 2}} \right)

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