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QJEEM21Mada22: JEE Main 2021 Mathematics - Class 11 JEEM21Mada22 Solution

The value of 3+14+13+14+13+....∞3 + {1 \over {4 + {1 \over {3 + {1 \over {4 + {1 \over {3 + ....\infty }}}}}}}} is equal to

Multiple Choice Options

  • A 1.5 + 3\sqrt 3
  • B 2 + 3\sqrt 3
  • C 3 + 2 3\sqrt 3
  • D 4 + 3\sqrt 3

Step-by-Step Verified Solution

Let x=3+14+13+14+13+....∞x = 3 + {1 \over {4 + {1 \over {3 + {1 \over {4 + {1 \over {3 + ....\infty }}}}}}}}

So, x=3+14+1x=3+14x+1xx = 3 + {1 \over {4 + {1 \over x}}} = 3 + {1 \over {{{4x + 1} \over x}}}

⇒(x−3)=x(4x+1)\Rightarrow (x - 3) = {x \over {(4x + 1)}}

⇒(4x+1)(x−3)=x\Rightarrow (4x + 1)(x - 3) = x

⇒4x2−12x+x−3=x\Rightarrow 4{x^2} - 12x + x - 3 = x

⇒4x2−12x−3=0\Rightarrow 4{x^2} - 12x - 3 = 0

x=12±(12)2+12×42×4=12±12(16)8x = {{12 \pm \sqrt {{{(12)}^2} + 12 \times 4} } \over {2 \times 4}} = {{12 \pm \sqrt {12(16)} } \over 8}

=12±4×238=3±232= {{12 \pm 4 \times 2\sqrt 3 } \over 8} = {{3 \pm 2\sqrt 3 } \over 2}

x=32±3=1.5±3x = {3 \over 2} \pm \sqrt 3 = 1.5 \pm \sqrt 3 .

But only positive value is accepted

So, x = 1.5+31.5 + \sqrt 3

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