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QJEEM21Mad8ec: JEE Main 2021 Mathematics - Class 11 JEEM21Mad8ec Solution: Let a point P be such that its distance from the point (5, 0)…

Let a point P be such that its distance from the point (5, 0) is thrice the distance of P from the point ( −- 5, 0). If the locus of the point P is a circle of radius r, then 4r2 is equal to ________

Step-by-Step Verified Solution

Let P(h, k)

Given

PA = 3PB

PA2 = 9PB2

⇒\Rightarrow (h −- 5)2 + k2 = 9[(h + 5)2 + k2]

⇒\Rightarrow 8h2 + 8k2 + 100h + 200 = 0

∴\therefore Locus

x2+y2+(252)x+25=0{x^2} + {y^2} + \left( {{{25} \over 2}} \right)x + 25 = 0

∴\therefore c≡(−254,0)c \equiv \left( {{{ - 25} \over 4},0} \right)

∴\therefore r2=(−254)2−25{r^2} = {\left( {{{ - 25} \over 4}} \right)^2} - 25

=62516−25= {{625} \over {16}} - 25

=22516= {{225} \over {16}}

∴\therefore 4r2=4×22516=2254=56.254{r^2} = 4 \times {{225} \over {16}} = {{225} \over 4} = 56.25

After Round of 4r2 = 56

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