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QJEEM21Macf2a: JEE Main 2021 Mathematics - Class 11 JEEM21Macf2a Solution: The least value of

The least value of |z| where z is complex number which satisfies the inequality exp⁡((∣z∣+3)(∣z∣−1)∣∣z∣+1∣log⁡e2)≥log⁡2∣57+9i∣,i=−1\exp \left( {{{(|z| + 3)(|z| - 1)} \over {||z| + 1|}}{{\log }_e}2} \right) \ge {\log _{\sqrt 2 }}|5\sqrt 7 + 9i|,i = \sqrt { - 1} , is equal to :

Multiple Choice Options

  • A 8
  • B 3
  • C 2
  • D 5\sqrt 5

Step-by-Step Verified Solution

Let | z | = t, t ≥\ge 0

e(t+3)(t−1)t+1log⁡e2≥log⁡216=8{e^{{{(t + 3)(t - 1)} \over {t + 1}}{{\log }_e}2}} \ge {\log _{\sqrt 2 }}16 = 8 ( ∵\because t + 1 > 0)

2(t+3)(t−1)t+1≥23{2^{{{(t + 3)(t - 1)} \over {t + 1}}}} \ge {2^3}

(t+3)(t−1)t+1≥3{{(t + 3)(t - 1)} \over {t + 1}} \ge 3

t2+2t−3≥3t+3{t^2} + 2t - 3 \ge 3t + 3

t2−t−6≥0{t^2} - t - 6 \ge 0

t∈(−∞,−2)∪[3,∞)t \in ( - \infty , - 2) \cup [3,\infty ) But t ≥\ge 0

∴\therefore t∈[3,∞)t \in [3,\infty )

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