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QJEEM21Mac207: JEE Main 2021 Mathematics - Class 12 JEEM21Mac207 Solution: The angle of elevation of a jet plane from a point A on the…

The angle of elevation of a jet plane from a point A on the ground is 60 ∘^\circ . After a flight of 20 seconds at the speed of 432 km/hour, the angle of elevation changes to 30 ∘^\circ . If the jet plane is flying at a constant height, then its height is :

Multiple Choice Options

  • A 360033600\sqrt 3 m
  • B 120031200\sqrt 3 m
  • C 180031800\sqrt 3 m
  • D 240032400\sqrt 3 m

Step-by-Step Verified Solution

JEE Main 2021 (Online) 24th February Evening Shift Mathematics - Height and Distance Question 18 English Explanation
v=432×100060×60v = 432 \times {{1000} \over {60 \times 60}} m/sec = 120 m/sec

Distance AB = v ×\times 20 = 2400 meter

In Δ\Delta PAC

tan⁡60∘=hPC⇒PC=h3\tan 60^\circ = {h \over {PC}} \Rightarrow PC = {h \over {\sqrt 3 }}

In Δ\Delta PBD

tan⁡30∘=hPD⇒PD=3h\tan 30^\circ = {h \over {PD}} \Rightarrow PD = \sqrt 3 h

PD = PC + CD

3h=h3+2400⇒2h3=2400\sqrt 3 h = {h \over {\sqrt 3 }} + 2400 \Rightarrow {{2h} \over {\sqrt 3 }} = 2400

h=12003h = 1200\sqrt 3 meter

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