QJEEM21Mab605: JEE Main 2021 Mathematics - Class 11 JEEM21Mab605 Solution: If one of the diameters of the circle x 2 + y 2 - 2x - 6y + 6 = …

Circle x² + y² - 2x - 6y + 6 = 0 has centre O₁(1, 3) and radius r = 2.

Let centre O₂ (2, 1) of required circle and its radius being r.


Distance between (1, 3) and (2, 1) is $$\sqrt{5}$$

$$\therefore$$ $${\left(\sqrt{5}\right)}^2+(2{)}^2=r^2$$

$$\Rightarrow r=3$$