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QJEEM21Maa90d: JEE Main 2021 Mathematics - Class 12 JEEM21Maa90d Solution: Consider the function where P(x) is a polynomial such that P''…

Consider the function


where P(x) is a polynomial such that P'' (x) is always a constant and P(3) = 9. If f(x) is continuous at x = 2, then P(5) is equal to _____________.JEE Main 2021 (Online) 25th July Evening Shift Mathematics - Limits, Continuity and Differentiability Question 110 English

Step-by-Step Verified Solution

f(x)={P(x)sin⁡(x−2),x≠27,x=2

P''(x) = const. ⇒\Rightarrow P(x) is a 2 degree polynomial

f(x) is cont. at x = 2

f(2+) = f(2 −- )

lim⁡x→2+P(x)sin⁡(x−2)=7\mathop {\lim }\limits_{x \to {2^ + }} {{P(x)} \over {\sin (x - 2)}} = 7

lim⁡x→2+(x−2)(ax+b)sin⁡(x−2)=7⇒2a+b=7\mathop {\lim }\limits_{x \to {2^ + }} {{(x - 2)(ax + b)} \over {\sin (x - 2)}} = 7 \Rightarrow 2a + b = 7

P(x) = (x −- 2)(ax + b)

P(3) = (3 −- 2)(3a + b) = 9 ⇒\Rightarrow 3a + b = 9

a = 2, b = 3

P(5) = (5 −- 2)(2.5 + 3) = 3.13 = 39

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