Verified Solution • 2025–26 Session moderate

QJEEM21Ma965d: JEE Main 2021 Mathematics - Class 11 JEEM21Ma965d Solution: Let n be a non-negative integer. Then the number of divisors of …

Let n be a non-negative integer. Then the number of divisors of the form "4n + 1" of the number (10)10 . (11)11 . (13)13 is equal to __________.

Step-by-Step Verified Solution

N = 210 ×\times 510 ×\times 1111 ×\times 1313

Now, power of 2 must be zero,

power of 5 can be anything,

power of 13 can be anything

But, power of 11 should be even.

So, required number of divisors is

1 ×\times 11 ×\times 14 ×\times 6 = 924

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