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QJEEM21Ma8ef7: JEE Main 2021 Mathematics - Class 11 JEEM21Ma8ef7 Solution: A possible value of 'x', for which the ninth term in the…

A possible value of 'x', for which the ninth term in the expansion of {3log325x−1+7+3(−18)log3(5x−1+1)}10 in the increasing powers of 3(−18)log3(5x−1+1) is equal to 180, is :

Multiple Choice Options

  • A 0
  • B −1
  • C 2
  • D 1

Step-by-Step Verified Solution

10C8(25(x−1)+7)×(5(x−1)+1)−1=180

⇒25x−1+75(x−1)+1=4

⇒t2+7t+1=4;

⇒ t = 1, 3 = 5x − 1

⇒ x − 1 = 0 (one of the possible value).

⇒ x = 1

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