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QJEEM21Ma8822: JEE Main 2021 Mathematics - Class 11 JEEM21Ma8822 Solution: If the coefficient of a 7 b 8 in the expansion of (a + 2b +…

If the coefficient of a7b8 in the expansion of (a + 2b + 4ab)10 is K.216, then K is equal to _____________.

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10!α!β!γ!aα(2b)β.(4ab)γ{{10!} \over {\alpha !\beta !\gamma !}}{a^\alpha }{(2b)^\beta }.{(4ab)^\gamma }

10!α!β!γ!aα+γ. bβ+γ . 2β . 4γ{{10!} \over {\alpha !\beta !\gamma !}}{a^{\alpha + \gamma }}.\,{b^{\beta + \gamma }}\,.\,{2^\beta }\,.\,{4^\gamma }

α+β+γ=10\alpha + \beta + \gamma = 10 ..... (1)

α+γ=7\alpha + \gamma = 7 .... (2)

β+γ=8\beta + \gamma = 8 ..... (3)

(2)+(3)−(1)⇒γ=5(2) + (3) - (1) \Rightarrow \gamma = 5

α=2\alpha = 2

β=3\beta = 3

so coefficients = 10!2!3!5!23.210{{10!} \over {2!3!5!}}{2^3}{.2^{10}}

=10×9×8×7×6×52×3×2×5!×213= {{10 \times 9 \times 8 \times 7 \times 6 \times 5} \over {2 \times 3 \times 2 \times 5!}} \times {2^{13}}

=315×216⇒k=315= 315 \times {2^{16}} \Rightarrow k = 315

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