Verified Solution • 2025–26 Session moderate

QJEEM21Ma8575: JEE Main 2021 Mathematics - Class 11 JEEM21Ma8575 Solution: Let S n denote the sum of first n-terms of an arithmetic…

Let Sn denote the sum of first n-terms of an arithmetic progression. If S10 = 530, S5 = 140, then S20 −- S6 is equal to:

Multiple Choice Options

  • A 1862
  • B 1842
  • C 1852
  • D 1872

Step-by-Step Verified Solution

Let first term of A.P. be a and common difference is d.

∴\therefore S10=102{2a+9d}=530{S_{10}} = {{10} \over 2}\{ 2a + 9d\} = 530

∴\therefore 2a+9d=1062a + 9d = 106 ..... (i)

S5=52{2a+4d}=140{S_5} = {5 \over 2}\{ 2a + 4d\} = 140

a+2d=28a + 2d = 28 ...... (ii)

From equation (i) and (ii), a = 8, d = 10

∴\therefore S20−S6=202{2×8+19×10}−62{2×8+5×10}{S_{20}} - {S_6} = {{20} \over 2}\{ 2 \times 8 + 19 \times 10\} - {6 \over 2}\{ 2 \times 8 + 5 \times 10\}

=2060−198= 2060 - 198

=1862= 1862

Related Learning Resources & Exam Preparation