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QJEEM21Ma8382: JEE Main 2021 Mathematics - Class 11 JEEM21Ma8382 Solution: Let z and be two complex numbers such that and Re( ) has…

Let z and ω\omega be two complex numbers such that ω=zz‾−2z+2,∣z+iz−3i∣=1\omega = z\overline z - 2z + 2,\left| {{{z + i} \over {z - 3i}}} \right| = 1 and Re( ω\omega ) has minimum value. Then, the minimum value of n ∈\in N for which ω\omega n is real, is equal to ______________.

Step-by-Step Verified Solution

Let z = x + iy

| z + i | = | z −- 3i |

⇒\Rightarrow y = 1

Now

ω\omega = x2 + y2 −- 2x −- 2iy + 2

ω\omega = x2 + 1 −- 2x −- 2i + 2

Re( ω\omega ) = x2 −- 2x + 3

Re( ω\omega ) = (x −- 1)2 + 2

Re( ω\omega )min at x = 1 ⇒\Rightarrow z = 1 + i

Now,

ω\omega = 1 + 1 −- 2 −- 2i + 2

ω\omega = 2(1 −- i) = 2 2ei(−π4)\sqrt 2 {e^{i\left( {{{ - \pi } \over 4}} \right)}}

ω\omega n = 2 2ei(−nπ4)\sqrt 2 {e^{i\left( {{{ - n\pi } \over 4}} \right)}}

If ω\omega n is real ⇒\Rightarrow n = 4

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