QJEEM21Ma6c59: JEE Main 2021 Mathematics - Class 11 JEEM21Ma6c59 Solution: The locus of the mid points of the chords of the hyperbola x 2…

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The locus of the mid points of the chords of the hyperbola x²

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y² = 4, which touch the parabola y² = 8x, is :

Accepted Answer

T = S₁

xh

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yk = h²

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k²

y = {{xh} \over k} - {{({h^2} - {k^2})} \over k}

this touches y² = 8x then

c = {a \over m}

\left( {{{{k^2} - {h^2}} \over k}} \right) = {{2k} \over h}

2y² = x(y²

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x²)

y²(x

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2) = x³

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