Verified Solution • 2025–26 Session moderate

QJEEM21Ma69ab: JEE Main 2021 Mathematics - Class 11 JEEM21Ma69ab Solution: The image of the point (3, 5) in the line x y + 1 = 0, lies on :

The image of the point (3, 5) in the line x −- y + 1 = 0, lies on :

Multiple Choice Options

  • A (x −- 4)2 + (y −- 4)2 = 8
  • B (x −- 4)2 + (y ++ 2)2 = 16
  • C (x −- 2)2 + (y −- 2)2 = 12
  • D (x −- 2)2 + (y −- 4)2 = 4

Step-by-Step Verified Solution

So, let the image is (x, y)

So, we have

x−31=y−5−1=−2(3−5+1)1+1{{x - 3} \over 1} = {{y - 5} \over { - 1}} = - {{2(3 - 5 + 1)} \over {1 + 1}}

⇒\Rightarrow x = 4, y = 4

⇒\Rightarrow Point (4, 4)

Which will satisfy the curve

(x −- 2)2 + (y −- 4)2 = 4

as (4 −- 2)2 + (4 −- 4)2 = 4 + 0 = 4

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