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QJEEM21Ma5aac: JEE Main 2021 Mathematics - Class 12 JEEM21Ma5aac Solution: Which of the following statements is correct for the function…

Which of the following statements is correct for the function g( α\alpha ) for α\alpha ∈\in R such that

g(α)=∫π6π3sin⁡αxcos⁡αx+sin⁡αxdxg(\alpha ) = \int\limits_{{\pi \over 6}}^{{\pi \over 3}} {{{{{\sin }^\alpha }x} \over {{{\cos }^\alpha }x + {{\sin }^\alpha }x}}dx}

Multiple Choice Options

  • A g(α)g(\alpha ) is a strictly increasing function
  • B g(α)g(\alpha ) is an even function
  • C g(α)g(\alpha ) has an inflection point at α\alpha = −- 12{1 \over 2}
  • D g(α)g(\alpha ) is a strictly decreasing function

Step-by-Step Verified Solution

g(α)=∫π/6π/3sin⁡α(π2−x)cos⁡α(π2−x)x+sin⁡α(π2−x)dxg(\alpha ) = \int\limits_{\pi /6}^{\pi /3} {{{{{\sin }^\alpha }\left( {{\pi \over 2} - x} \right)} \over {{{\cos }^\alpha }\left( {{\pi \over 2} - x} \right)x + {{\sin }^\alpha }\left( {{\pi \over 2} - x} \right)}}dx}

=∫π/6π/3cos⁡αxsin⁡αx+cos⁡αxdx= \int\limits_{\pi /6}^{\pi /3} {{{{{\cos }^\alpha }x} \over {{{\sin }^\alpha }x + {{\cos }^\alpha }x}}dx}

∴\therefore 2.g(α)=∫π/6π/3sinαx+cos⁡αxsin⁡αx+cos⁡αxdx=∫π/6π/3dx=π3−π6=π62.g(\alpha ) = \int\limits_{\pi /6}^{\pi /3} {{{si{n^\alpha }x + {{\cos }^\alpha }x} \over {{{\sin }^\alpha }x + {{\cos }^\alpha }x}}dx} = \int\limits_{\pi /6}^{\pi /3} {dx} = {\pi \over 3} - {\pi \over 6} = {\pi \over 6}

⇒\Rightarrow g(α)=π12g(\alpha ) = {\pi \over {12}} i.e. a constant function hence an even function.

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