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QJEEM21Ma4e2c: JEE Main 2021 Mathematics - Class 12 JEEM21Ma4e2c Solution: A fair die is tossed until six is obtained on it. Let x be the…

A fair die is tossed until six is obtained on it. Let x be the number of required tosses, then the conditional probability P(x ≥\ge 5 | x > 2) is :

Multiple Choice Options

  • A 125216{{125} \over {216}}
  • B 1136{{11} \over {36}}
  • C 56{{5} \over {6}}
  • D 2536{{25} \over {36}}

Step-by-Step Verified Solution

P(x ≥\ge 5 | x > 2) = {{P(x \ge 5)} \over {P(x > 2)}}

= (56)4.16+(56)5.16+.......+∞(56)2.16+(56)3.16+......+∞{{{{\left( {{5 \over 6}} \right)}^4}.{1 \over 6} + {{\left( {{5 \over 6}} \right)}^5}.{1 \over 6} + ....... + \infty } \over {{{\left( {{5 \over 6}} \right)}^2}.{1 \over 6} + {{\left( {{5 \over 6}} \right)}^3}.{1 \over 6} + ...... + \infty }}

= (56)4.151−56(56)2.161−56=(56)2=2536{{{{{{\left( {{5 \over 6}} \right)}^4}.{1 \over 5}} \over {1 - {5 \over 6}}}} \over {{{{{\left( {{5 \over 6}} \right)}^2}.{1 \over 6}} \over {1 - {5 \over 6}}}}} = {\left( {{5 \over 6}} \right)^2} = {{25} \over {36}}

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