Verified Solution • 2025–26 Session moderate

QJEEM21Ma4e0e: JEE Main 2021 Mathematics - Class 12 JEEM21Ma4e0e Solution: Let f : R → R be defined as f ( x ) = { 2 sin ⁡ ( − π x 2 ) , i …

Let f : R → R be defined as

f(x)={2sin⁡(−πx2),ifx<−1|ax2+x+b|,if−1≤x≤1sin⁡(πx),ifx>1 If f(x) is continuous on R, then a + b equals :

Multiple Choice Options

  • A −3
  • B 3
  • C −1
  • D 1

Step-by-Step Verified Solution

f(−1−)=2

f(−1+)=|a+b−1|

|a+b−1|=2 ... (i)

f(1−)=|a+b+1|

f(1+)=0

|a+b+1|=0⇒a+b+1=0

⇒a+b=−1 .... (ii)

Related Learning Resources & Exam Preparation