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QJEEM21Ma4ad9: JEE Main 2021 Mathematics - Class 11 JEEM21Ma4ad9 Solution: If , R are such that 1 2i (here i 2 = 1) is a root of z 2 + z + …

If α\alpha , β\beta ∈\in R are such that 1 −- 2i (here i2 = −- 1) is a root of z2 + α\alpha z + β\beta = 0, then ( α\alpha −- β\beta ) is equal to :

Multiple Choice Options

  • A −- 7
  • B 7
  • C 3
  • D −- 3

Step-by-Step Verified Solution

1 −- 2i is the root of the equation. So other root is 1 ++ 2i

∴\therefore Sum of roots = 1 −- 2i + 1 ++ 2i = 2 = - α\alpha

Product of roots = (1 −- 2i)(1 ++ 2i) = 1 - 4i2 = 5 = β\beta

∴\therefore α\alpha - β\beta = -2 - 5 = -7

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