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QJEEM21Ma3bd0: JEE Main 2021 Mathematics - Class 11 JEEM21Ma3bd0 Solution: For the four circles M, N, O and P, following four equations…
For the four circles M, N, O and P, following four equations are given :
Circle M : x2 + y2 = 1
Circle N : x2 + y2 2x = 0
Circle O : x2 + y2 2x 2y + 1 = 0
Circle P : x2 + y2 2y = 0
If the centre of circle M is joined with centre of the circle N, further center of circle N is joined with centre of the circle O, centre of circle O is joined with the centre of circle P and lastly, centre of circle P is joined with centre of circle M, then these lines form the sides of a :
Circle M : x2 + y2 = 1
Circle N : x2 + y2
Circle O : x2 + y2
Circle P : x2 + y2
If the centre of circle M is joined with centre of the circle N, further center of circle N is joined with centre of the circle O, centre of circle O is joined with the centre of circle P and lastly, centre of circle P is joined with centre of circle M, then these lines form the sides of a :
Multiple Choice Options
- A Rhombus
- B Square
- C Rectangle
- D Parallelogram
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