Verified Solution • 2025–26 Session moderate

QJEEM21Ma30ec: JEE Main 2021 Mathematics - Class 12 JEEM21Ma30ec Solution: When a certain biased die is rolled, a particular face occurs…

When a certain biased die is rolled, a particular face occurs with probability 16−x{1 \over 6} - x and its opposite face occurs with probability 16+x{1 \over 6} + x . All other faces occur with probability 16{1 \over 6} . Note that opposite faces sum to 7 in any die. If 0 < x < 16{1 \over 6} , and the probability of obtaining total sum = 7, when such a die is rolled twice, is 1396{13 \over 96} , then the value of x is :

Multiple Choice Options

  • A 116{1 \over 16}
  • B 18{1 \over 8}
  • C 19{1 \over 9}
  • D 112{1 \over 12}

Step-by-Step Verified Solution

Probability of obtaining total sum 7 = probability of getting opposite faces.

Probability of getting opposite faces

=2[(16−x)(16+x)+16×16+16×16]= 2\left[ {\left( {{1 \over 6} - x} \right)\left( {{1 \over 6} + x} \right) + {1 \over 6} \times {1 \over 6} + {1 \over 6} \times {1 \over 6}} \right]

⇒2[(16−x)(16+x)+16×16+16×16]=1396\Rightarrow 2\left[ {\left( {{1 \over 6} - x} \right)\left( {{1 \over 6} + x} \right) + {1 \over 6} \times {1 \over 6} + {1 \over 6} \times {1 \over 6}} \right] = {{13} \over {96}} (given)

⇒\Rightarrow x=18x = {1 \over 8}

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