Verified Solution • 2025–26 Session moderate

QJEEM21Ma18cd: JEE Main 2021 Mathematics - Class 11 JEEM21Ma18cd Solution: Let A be a fixed point (0, 6) and B be a moving point (2t, 0).…

Let A be a fixed point (0, 6) and B be a moving point (2t, 0). Let M be the mid-point of AB and the perpendicular bisector of AB meets the y-axis at C. The locus of the mid-point P of MC is :

Multiple Choice Options

  • A 3x2 − 2y − 6 = 0
  • B 3x2 + 2y − 6 = 0
  • C 2x2 + 3y − 9 = 0
  • D 2x2 − 3y + 9 = 0

Step-by-Step Verified Solution

A(0, 6) and B(2t, 0)

JEE Main 2021 (Online) 27th August Morning Shift Mathematics - Straight Lines and Pair of Straight Lines Question 68 English Explanation

Perpendicular bisector of AB is

(y−3)=t3(x−t)

So, C=(0,3−t23)

Let P be (h, k)

h=t2;k=(3−t26)

⇒k=3−4h26⇒2x2+3y−9=0

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