QJEEM21Ma145e: JEE Main 2021 Mathematics - Class 11 JEEM21Ma145e Solution: Consider the following frequency distribution : .tg…

$\because$ Sum of frequencies = 584

$\Rightarrow$ $\alpha$ + $\beta$ = 390

Now, median is at ${{584} \over 2}$ = 292^th

$\because$ Median = 45 (lies in class 40 - 50)

$\Rightarrow$ $\alpha$ + 110 + 54 + 15 = 292

$\Rightarrow$ $\alpha$ = 113, $\beta$ = 277

$\Rightarrow$ | $\alpha$ $-$ $\beta$ | = 164