Verified Solution • 2025–26 Session moderate

QJEEM21Ma128f: JEE Main 2021 Physics - Class 11 JEEM21Ma128f Solution: Let a → = i ^ + 5 j ^ + α k ^ , b → = i ^ + 3 j ^ + β k ^ and c …

Let a→=i^+5j^+αk^, b→=i^+3j^+βk^ and c→=−i^+2j^−3k^ be three vectors such that, |b→×c→|=53 and a→ is perpendicular to b→. Then the greatest amongst the values of |a→|2 is _____________.

Step-by-Step Verified Solution

Since, a→.b→=0

1+15+αβ=0⇒αβ=−16 .... (1)

Also,

|b→×c→|2=75⇒(10+β2)14−(5−3β)2=75

⇒ 5β2 + 30β + 40 = 0

⇒ β = −4, −2

⇒ α = 4, 8

⇒|a→|max2=(26+α2)max=90

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