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QJEEM21Ma0f38: JEE Main 2021 Mathematics - Class 12 JEEM21Ma0f38 Solution: If y = y(x) is the solution of the differential equation + (tan …

If y = y(x) is the solution of the differential equation

dydx{{dy} \over {dx}} + (tan x) y = sin x, 0≤x≤π30 \le x \le {\pi \over 3} , with y(0) = 0, then y(π4)y\left( {{\pi \over 4}} \right) equal to :

Multiple Choice Options

  • A 12{1 \over 2} loge 2
  • B (122)\left( {{1 \over {2\sqrt 2 }}} \right) loge 2
  • C loge 2
  • D 14{1 \over 4} loge 2

Step-by-Step Verified Solution

Integrating Factor =e∫tan⁡x dx=eln⁡(sec⁡x)=sec⁡x= {e^{\int {\tan x\,dx} }} = {e^{\ln (\sec x)}} = \sec x

ysec⁡x=∫(sin⁡x)sec⁡x dx=ln⁡(sec⁡x)+Cy\sec x = \int {(\sin x)\sec x\,dx = \ln (\sec x) + C}

y(0)=0⇒C=0y(0) = 0 \Rightarrow C = 0

∴\therefore y=cos⁡xln⁡∣sec⁡x∣y = \cos x\ln |\sec x|

y(π4)=12ln⁡(2)=122ln⁡2y\left( {{\pi \over 4}} \right) = {1 \over {\sqrt 2 }}\ln \left( {\sqrt 2 } \right) = {1 \over {2\sqrt 2 }}\ln 2

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