Verified Solution • 2025–26 Session moderate

QJEEM21Ma0eac: JEE Main 2021 Mathematics - Class 12 JEEM21Ma0eac Solution: Let f(x) be a differentiable function at x = a with f'(a) = 2…

Let f(x) be a differentiable function at x = a with f'(a) = 2 and f(a) = 4.

Then limx→a⁡xf(a)−af(x)x−a equals :

Multiple Choice Options

  • A 4 − 2a
  • B 2a + 4
  • C a + 4
  • D 2a − 4

Step-by-Step Verified Solution

L=limx→a⁡xf(a)−af(x)x−a [00 form]

Using L' Hospital rule we get

L=limx→a⁡f(a)−af′(x)1

f(a)−af′(a)=4−2a

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