Verified Solution • 2025–26 Session moderate

QJEEM21Ma0da6: JEE Main 2021 Mathematics - Class 12 JEEM21Ma0da6 Solution: If , x > 2, and (0) = 4, then (2) is __________.

If xϕ(x)=∫5x(3t2−2ϕ′(t))dtx\phi (x) = \int\limits_5^x {(3{t^2} - 2\phi '(t))dt} , x > −- 2, and ϕ\phi (0) = 4, then ϕ\phi (2) is __________.

Step-by-Step Verified Solution

xϕ(x)=∫5x3t2−2ϕ′(t)dtx\phi (x) = \int\limits_5^x {3{t^2} - 2\phi '(t)dt}

xϕ(x)=x3−125−2[ϕ(x)−ϕ(5)]x\phi (x) = {x^3} - 125 - 2[\phi (x) - \phi (5)]

xϕ(x)=x3−125−2ϕ(x)−2ϕ(5)x\phi (x) = {x^3} - 125 - 2\phi (x) - 2\phi (5)

ϕ(0)=4⇒ϕ(5)=1332\phi (0) = 4 \Rightarrow \phi (5) = {{133} \over 2}

ϕ(x)=x3+8x+2\phi (x) = {{{x^3} + 8} \over {x + 2}}

ϕ(2)=4\phi (2) = 4

Related Learning Resources & Exam Preparation