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QJEEM21Ma0a33: JEE Main 2021 Mathematics - Class 11 JEEM21Ma0a33 Solution: Let P 1 , P 2 , ......, P 15 be 15 points on a circle. The…

Let P1, P2, ......, P15 be 15 points on a circle. The number of distinct triangles formed by points Pi, Pj, Pk such that i +j + k ≠\ne 15, is :

Multiple Choice Options

  • A 12
  • B 419
  • C 443
  • D 455

Step-by-Step Verified Solution

Total number of triangles = 15C3{}^{15}{C_3}

i + j + k = 15 (Given)

JEE Main 2021 (Online) 1st September Evening Shift Mathematics - Permutations and Combinations Question 103 English Explanation
Number of possible triangles using the vertices Pi, Pj, Pk such that i + j + k ≠\ne 15 is equal to 15C3{}^{15}{C_3} −- 12 = 443

Option (c)

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