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QJEEM21Ma0789: JEE Main 2021 Physics - Class 11 JEEM21Ma0789 Solution: In a triangle ABC, if , then the projection of the vector on is …

In a triangle ABC, if ∣BC→∣=8,∣CA→∣=7,∣AB→∣=10|\overrightarrow {BC} | = 8,|\overrightarrow {CA} | = 7,|\overrightarrow {AB} | = 10 , then the projection of the vector AB→\overrightarrow {AB} on AC→\overrightarrow {AC} is equal to :

Multiple Choice Options

  • A 254{{25} \over 4}
  • B 12720{{127} \over 20}
  • C 8514{{85} \over 14}
  • D 11516{{115} \over 16}

Step-by-Step Verified Solution

JEE Main 2021 (Online) 18th March Evening Shift Mathematics - Vector Algebra Question 151 English Explanation
∣a→∣=8,∣b→∣=7,∣c→∣=10|\overrightarrow a | = 8,|\overrightarrow b | = 7,|\overrightarrow c | = 10

Projection of AB→\overrightarrow {AB} on AC→\overrightarrow {AC}

= ∣AB→∣cosθ|\overrightarrow {AB} |cos\theta

=10(∣AB→∣2+∣CA→∣2−∣BC→∣22.∣CA→∣∣AB→∣)= 10\left( {{{|\overrightarrow {AB} {|^2} + |\overrightarrow {CA} {|^2} - |\overrightarrow {BC} {|^2}} \over {2.|\overrightarrow {CA} ||\overrightarrow {AB} {|}}}} \right)

=10(102+72−822(10)(7))= 10\left( {{{{{10}^2} + {7^2} - {8^2}} \over {2(10)(7)}}} \right)

=10(85140)= 10\left( {{{85} \over {140}}} \right)

=8514= {{85} \over {14}}

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