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QJEEM21Ma0602: JEE Main 2021 Mathematics - Class 12 JEEM21Ma0602 Solution: Let the functions f : R R and g : R R be defined as : f ( x ) = …

Let the functions f : R →\to R and g : R →\to R be defined as :

f(x)={x+2,x<0x2,x≥0 and

g(x)={x3,x<13x−2,x≥1

Then, the number of points in R where (fog) (x) is NOT differentiable is equal to :

Multiple Choice Options

  • A 0
  • B 3
  • C 1
  • D 2

Step-by-Step Verified Solution

fog(x)={x3+2,x≤0x6,0≤x≤1(3x−2)2,x≥1

∵\because fog(x) is discontinuous at x = 0 then non-differentiable at x = 0

Now,

at x = 1

RHD=lim⁡h→0f(1+h)−f(1)h=lim⁡h→0(3(1+h)−2)2−1h=6RHD = \mathop {\lim }\limits_{h \to 0} {{f(1 + h) - f(1)} \over h} = \mathop {\lim }\limits_{h \to 0} {{{{(3(1 + h) - 2)}^2} - 1} \over h} = 6

LHD=lim⁡h→0f(1−h)−f(1)−h=lim⁡h→0(1−h)6−1−h=6LHD = \mathop {\lim }\limits_{h \to 0} {{f(1 - h) - f(1)} \over { - h}} = \mathop {\lim }\limits_{h \to 0} {{{{(1 - h)}^6} - 1} \over { - h}} = 6

Number of points of non-differentiability = 1

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