QJEEM21Chfe6f: JEE Main 2021 Chemistry - Class 12 JEEM21Chfe6f Solution: The spin only magnetic moment of a divalent ion in aqueous…

Z = 29 [Cu] $$\stackrel{-2e^{-}}{⟶}$$ Cu²⁺ = [Ar] 3d⁹

Number of unpaired electron, n = 1

$\therefore$ Spin only magnetic moment,

$\mu = \sqrt {n(n + 2)} BM = \sqrt {1(1 + 2)} BM = \sqrt 3 BM$

= 1.73 BM $\simeq$ 2 BM