Verified Solution • 2025–26 Session moderate

QJEEM21Chf470: JEE Main 2021 Chemistry - Class 12 JEEM21Chf470 Solution: 1 molal aqueous solution of an electrolyte A 2 B 3 is 60%…

1 molal aqueous solution of an electrolyte A2B3 is 60% ionised. The boiling point of the solution at 1 atm is _________ K. (Rounded off to the nearest integer)

[Given Kb for (H2O) = 0.52 K kg mol −- 1]

Step-by-Step Verified Solution

A2B3⟶2A+3+3B−2

No. of ions = 2 + 3 = 5

i = 1 + (n −- 1) α\alpha

= 1 + (5 −- 1) ×\times 0.6

= 1 + 4 ×\times 0.6 = 1 + 2.4 = 3.4

ΔTb=Kb×m×i=0.52×1×3.4=1.768∘\Delta {T_b} = {K_b} \times m \times i = 0.52 \times 1 \times 3.4 = 1.768^\circ C

ΔTb=(Tb)solution−[(Tb)H2O]Solution\Delta {T_b} = {({T_b})_{solution}} - {[{({T_b})_{{H_2}O}}]_{Solution}}

1.768=(Tb)solution−1001.768 = {({T_b})_{solution}} - 100

(Tb)solution=101.768∘{({T_b})_{solution}} = 101.768^\circ C

=375= 375 K

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