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QJEEM21Chf04a: JEE Main 2021 Chemistry - Class 12 JEEM21Chf04a Solution: An aqueous solution of NiCl 2 was heated with excess sodium…

An aqueous solution of NiCl2 was heated with excess sodium cyanide in presence of strong oxidizing agent to form [Ni(CN)6]2 −- . The total change in number of unpaired electrons on metal centre is _______________.

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[Ni(CN)6]2-

Ni+4 →\to d6, CN- strong field ligand. So pairing will happen.

JEE Main 2021 (Online) 20th July Evening Shift Chemistry - Coordination Compounds Question 166 English Explanation 1

Here zero unpaired electron

NiCl2 →\to Ni2+ →\to d8

JEE Main 2021 (Online) 20th July Evening Shift Chemistry - Coordination Compounds Question 166 English Explanation 2Cl- Weak field ligand. →\to two unpaired e-

∴\therefore Change = 2.

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