QJEEM21Cheeb4: JEE Main 2021 Chemistry - Class 11 JEEM21Cheeb4 Solution: The exact volumes of 1 M NaOH solution required to neutralise…

Millimoles of H₃PO₃ = M $$\times$$ V = 1 $$\times$$ 50 = 50

For 1 millimole of H₃PO₃, we require 2 millimoles of NaOH.

For 50 millimole of H₃PO₃, we require (2 $$\times$$ 50) = 100 millimoles of NaOH.

Millimoles of NaOH = M $$\times$$ V = 100

1 $$\times$$ V = 100

V = 100 mL

Millimoles of H₃PO₂ = M $$\times$$ V = 2 $$\times$$ 100 = 200

For 1 millimole of H₃PO₂, we require 1 millimoles of NaOH.

For 200 millimoles of H₃PO₂, we require 200 millimoles of NaOH.

So, volume of NaOH = 200 mL