Verified Solution • 2025–26 Session moderate

QJEEM21Cheddb: JEE Main 2021 Chemistry - Class 11 JEEM21Cheddb Solution: 100 g of propane is completely reacted with 1000 g of oxygen.…

100 g of propane is completely reacted with 1000 g of oxygen. The mole fraction of carbon dioxide in the resulting mixture is x ×\times 10 −- 2. The value of x is ____________. (Nearest integer)

[Atomic weight : H = 1.008; C = 12.00; O = 16.00]

Step-by-Step Verified Solution

C3H8(g) + 5O2(g) →\to 3CO2(g) + 4H2O(l)

t = 0 2.27 mole 31.25 mol
t = ∞\infty 0 19.9 mol 6.81 mol 9.08 mol


mole fraction of CO2 in the final reaction mixture (heterogenous)

XCO2=6.8119.9+6.81+9.08{X_{C{O_2}}} = {{6.81} \over {19.9 + 6.81 + 9.08}}

= 0.1902 = 19.02 ×\times 10 −- 2

⇒\Rightarrow 19

Related Learning Resources & Exam Preparation