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QJEEM21Chea99: JEE Main 2021 Chemistry - Class 11 JEEM21Chea99 Solution: Methylation of 10 g of benzene gave 9.2 g of toluene. Calculate …

Methylation of 10 g of benzene gave 9.2 g of toluene. Calculate the percentage yield of toluene __________. (Nearest integer)

Step-by-Step Verified Solution

C6H6+CH3Cl⟶C6H5CH3+HCl{C_6}{H_6} + C{H_3}Cl\mathrel{\mathop{\kern0pt\longrightarrow}\limits_{}} {C_6}{H_5}C{H_3} + HCl

10 gm of C6H6 = 1078{{10} \over {78}} mole

Moles of methylbenzene should be obtained = 1078{{10} \over {78}} mole

= (1078×92)gm\left( {{{10} \over {78}} \times 92} \right)gm

∴\therefore AyTy=%{{{A_y}} \over {{T_y}}} = \% yield =9.2920×78×100⇒78%= {{9.2} \over {920}} \times 78 \times 100 \Rightarrow 78\%

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