Verified Solution • 2025–26 Session moderate

QJEEM21Che58d: JEE Main 2021 Chemistry - Class 11 JEEM21Che58d Solution: 10.0 mL of 0.05 M KMnO 4 solution was consumed in a titration…

10.0 mL of 0.05 M KMnO4 solution was consumed in a titration with 10.0 mL of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is _________ × 10−2 g/L.

(Round off to the nearest integer)

Step-by-Step Verified Solution

neq KMnO4 = neq H2C2O4 . 2H2O

or, 10×0.051000×5=10×M1000×2

∴ Conc. of oxalic acid solution = 0.125 M

= 0.125 × 125 g/L = 15.75 g/L

= 1575 × 10−2 g/L

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