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QJEEM21Che2fe: JEE Main 2021 Chemistry - Class 12 JEEM21Che2fe Solution: If a compound AB dissociates to the extent of 75% in an aqueous …

If a compound AB dissociates to the extent of 75% in an aqueous solution, the molality of the solution which shows a 2.5 K rise in the boiling point of the solution is ____________ molal. (Rounded off to the nearest integer)

[Kb = 0.52 K kg mol −- 1]

Step-by-Step Verified Solution

As AB is a binary electrolyte,

∴\therefore AB ⇌\rightleftharpoons A+ + B −- , n = 2

i=1+α(n−1)=1+75100(2−1)=1.75i = 1 + \alpha (n - 1) = 1 + {{75} \over {100}}(2 - 1) = 1.75

Given, Δ\Delta Tb = 2.5 K

Kb = 0.52 K kg mol −- 1

∴\therefore Δ\Delta Tb = Kb ×\times m ×\times i

⇒m=ΔTbKb×i=2.50.52×1.75\Rightarrow m = {{\Delta {T_b}} \over {{K_b} \times i}} = {{2.5} \over {0.52 \times 1.75}}

=2.74≃3= 2.74 \simeq 3 mol/kg

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