Verified Solution • 2025–26 Session moderate

QJEEM21Che292: JEE Main 2021 Chemistry - Class 11 JEEM21Che292 Solution: The OH concentration in a mixture of 5.0 mL of 0.0504 M NH 4 Cl …

The OH −- concentration in a mixture of 5.0 mL of 0.0504 M NH4Cl and 2 mL of 0.0210 M NH3 solution is x ×\times 10 −- 6 M. The value of x is ___________. (Nearest integer)

[Given Kw = 1 ×\times 10 −- 14 and Kb = 1.8 ×\times 10 −- 5]

Step-by-Step Verified Solution

[NH4+]\left[ {NH_4^ + } \right] = 0.0504 & [NH3] = 0.0210

So, Kb=[NH4+][HO−][NH3]{K_b} = {{[NH_4^ + ][H{O^ - }]} \over {[N{H_3}]}}

[HO−]=Kb×[NH3][NH4+]=1.8×10−5×25×210504=3×10−6[H{O^ - }] = {{{K_b} \times [N{H_3}]} \over {[NH_4^ + ]}} = 1.8 \times {10^{ - 5}} \times {2 \over 5} \times {{210} \over {504}} = 3 \times {10^{ - 6}}

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