Verified Solution • 2025–26 Session
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QJEEM21Chdacc: JEE Main 2021 Chemistry - Class 11 JEEM21Chdacc Solution: Match List - I with List - II. List I (Salt) List II (Flame…
Match List - I with List - II.
Choose the correct answer from the options given below :
| List I (Salt) | List II (Flame colour wavelength) | ||
|---|---|---|---|
| (a) | LiCl | (i) | 455.5 nm |
| (b) | NaCl | (ii) | 670.8 nm |
| (c) | RbCl | (iii) | 780.0 nm |
| (d) | CsCl | (iv) | 589.2 nm |
Choose the correct answer from the options given below :
Multiple Choice Options
- A (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
- B (a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)
- C (a)-(i), (b)-(iv), (c)-(ii), (d)-(iii)
- D (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
Step-by-Step Verified Solution
| Alkali metal | Colour (Flame) | (nm) |
|---|---|---|
| Li | Crimson red | 670.8 |
| Na | Yellow | 589.2 |
| Rb | Red, violet | 780.0 |
| Cs | Blue | 455.5 |
Alkali metals have very low value of ionisation energy as compared to other metals. So, alkali metals easily get excited and impart colour to flame.
Hence, Rb is most excited and having high value of wavelength in all alkali metals.