Verified Solution • 2025–26 Session moderate

QJEEM21Chd940: JEE Main 2021 Chemistry - Class 12 JEEM21Chd940 Solution: When 3.00 g of a substance 'X' is dissolved in 100 g of CCl 4 , …

When 3.00 g of a substance 'X' is dissolved in 100 g of CCl4, it raises the boiling point by 0.60 K. The molar mass of the substance 'X' is ______________ g mol −- 1. (Nearest integer).

[Given Kb for CCl4 is 5.0 K kg mol −- 1]

Step-by-Step Verified Solution

Δ\Delta Tb = Kb ×\times molality

0.60 = 5 ×\times (3/M100/100)\left( {{{3/M} \over {100/100}}} \right)

M = 250

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