QJEEM21Chd5a7: JEE Main 2021 Chemistry - Class 12 JEEM21Chd5a7 Solution: Consider the following reaction M n O 4 − + 8 H + + 5 e − → M n …

Question

Verified Solution • 2025–26 Session moderate

Consider the following reaction

M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{+ 2} + 4 H_{2} O, E^{o} = 1.51 V

.

The quantity of electricity required in Faraday to reduce five moles of

M n O_{4}^{-}

is ___________. (Integer answer)

Accepted Answer

M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{+ 2} + 4 H_{2} O, E^{o} = 1.51 V

1 mole of MnO₄^- required 5 moles of electrons or 5 F electricity.

∴

5 moles of MnO₄^- required 25 F electricity.

Step-by-Step Verified Solution