QJEEM21Chd14e: JEE Main 2021 Chemistry - Class 11 JEEM21Chd14e Solution: 100 mL of Na 3 PO 4 solution contains 3.45 g of sodium. The…

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100 mL of Na₃PO₄ solution contains 3.45 g of sodium. The molarity of the solution is _____________

\times

10^{$-$ 2} mol L^{$-$ 1}. (Nearest integer)

[Atomic Masses - Na : 23.0 u, O : 16.0 u, P : 31.0 u]

Accepted Answer

Molarity of Na₃PO₄ Solution =

{{{n_{N{a_3}P{O_4}}}} \over {volume\,of\,solution\,in\,L}}

= {{{1 \over 3} \times {{3.45} \over {23}}mol} \over {0.1\,L}}

= 0.5 = 50

\times

10^{$-$ 2}

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